Number of ways in which 25 identical things be distributed among five persons if each gets odd number of things is

Let person Pi gets xi number of things such that     x1+x2+x3+x4+x5=25Let xi=2λi+1, where λi≥0. Then      2λ1+λ2+λ3+λ4+λ5+5=25or  λ1+λ2+λ3+λ4+λ5=10We have to simply obtain the number of non-negative integral solutions of this equation, which is equal to 14C4.