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The number of ways in which 5 ladies and 7 gentlemen can be seated in a round table so that no two ladies sit together, is

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a
72(720)2
b
7(360)2
c
7(720)2
d
720

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detailed solution

Correct option is A

First we fix the alternate positions of z gentlemen in a round table by 6! ways.There are seven positions between the gentlemen in which 5 ladies can be seated in  7P5. ways. Required number of ways                                     =6!×7!2!=72(720)2


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