The number of ways in which two teams A and B of 11 players each can be made up from 22 players so that two particular players are on the opposite sides is
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a
369512
b
184755
c
184756
d
369514
answer is A.
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Detailed Solution
We can choose 10 players from (22 – 2) players in C10 20 ways and one player from 2 players in C1 2 ways.∴ required number of ways =20!10!10!×2=369512