Questions
Number of zeros at then end of is
a
2
b
4
c
1002
d
1004
detailed solution
Correct option is A
Let n=1001, we can write991001+1=(100−1)n+1 =nC0100n−nC1100n−1+nC2100n−2−… =100m+nCn−1(100)−1+1where m=nC0100n−1−nC1100n−2+nC2100n−3−…−nCn−2100+nCn−1As nCn−1=1001,the units digit of m is different from 0. Thus, the number of zeros at the end of 991001+1is two.Talk to our academic expert!
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