First slide
Evaluation of definite integrals
Question

The numbers A, B and C such that a function of the form f (x) = A x2 + Bx + C satisfies the conditions

f(1)=8,f(2)+f′′(2)=33 and 01f(x)dx=7/3 are

Moderate
Solution

8=f(1)=2A+B33=f(2)+f′′(2)=6A+2B+C Also, 73=13A+12B+C14=2A+3B+6C

Solving we obtain

A=7,B=6,C=3

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