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The numbers $A, B$ and C such that a function of the form $f (x) = A x 2 + B x + C$ satisfies the conditions
$f^{'} (1) = 8, f (2) + f^{''} (2) = 33$ and $\int_{0}^{1} f (x) d x = 7 / 3$ are

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A = 1, B = – 4, C = 2

A=7,B=–6, C=3

A=8,B=−6,C=3

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detailed solution

Correct option is B

8=f′(1)=2A+B33=f(2)+f′′(2)=6A+2B+C Also, 73=13A+12B+C⇒14=2A+3B+6CSolving we obtainA=7,B=–6,C=3

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The numbers A, B and C such that a function of the form f (x) = A x2 + Bx + C satisfies the conditionsf′(1)=8,f(2)+f′′(2)=33 and ∫01 f(x)dx=7/3 are

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Ready to Test Your Skills?

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The numbers $A, B$ and C such that a function of the form $f (x) = A x 2 + B x + C$ satisfies the conditions
$f^{'} (1) = 8, f (2) + f^{''} (2) = 33$ and $\int_{0}^{1} f (x) d x = 7 / 3$ are