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Questions  

The numbers 1,2,3, ..., n are arrange in a random order. The probability that the digits 1, 2, 3, . . ., k (k < n) appear as neighbors in that order is

a
1n!
b
k!n!
c
(n-k)!n!
d
n-k+1!n!

detailed solution

Correct option is D

The number of ways of arranging n numbers is n! In each order obtained, we must now arrange the digits 1, 2, ..., k as group and the n - k remaining digits. This can be done in (n - k + l)! ways. Therefore, the probability for the required event isn-k+1!n!

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