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a
-25
b
-12
c
40
d
53
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Correct option is D
28=32sin2α−1+34−2sin2α since 2b=a+c Let a=32sin2α28=a3+34a→a2−84a+243=0→a=81,3 If a=3→32sin2α=31 if a=81 then sin2α=2 which is not possible →sin2α=1/2→2α=30α=15∘ the first three terms are 1,14,27 Then t5=a+4d=1+52=53Similar Questions
The sum of terms of an is The number of term which equals 159, is
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