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Questions  

 The numericall6y greatest term in the expansion of (3+2x)49 when x=1/5 is 

a
4th term
b
5th term
c
6th term
d
7th term

detailed solution

Correct option is C

(3+2x)49=349(1+2x/3)49=349(1+α)49 where α=2x3=2(1/5)3=215(n+1)|α||α|+1=100/1517/15=10017=5+1517∴6th  term is the numerically greatest.

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