The numerically greatest term in the expansion (5x– 6y)14  when x=25,y=12 is

Given expansion (5x– 6y)14  is (5x−6y)14=(5x)14(1−6y5x)14  this expansion covert into (1+x)n The numerically greatest term in the expansion of(1+x)n is (n+1)|x||x|+1 N.G.T=15|6×125×25|32+1=9  We have general term in the expansion (x+a)n (∴  Tr+1= nCr xn−r (a)r  be the expansion of (x+a)n) T9=T8+1=14C8 (5x)6 (−6y)8........................(1) Substitute these values in Eqn (1)x=25,y=12  then we get      T9=14C8 26× 38 is the numerically greatest term in the given expansion