The numerically greatest term of (2x-3y)12 where x=1;y=1

(2x−3y)12=(2x)121−3y2x12n=12;X=−3y2x Where x=1;y=1 Then X=-32now(n+1)XX+1=(12+1)×3232+1                                           =13×3252                                         =395                                          =7.8                                         =7+0.8                      = P + F∴ Numerically greatest term is TP+1=T88th  term