Questions
One diagonal of a square is along the line 8x - l5y=0 and one of its vertex is ( l, 2). Then the equations of the sides ofthe square passing through this vertex are
a
23x+7y=9,7x+23y=53
b
23x−7y+9=0,7x+23y+53=0
c
23x−7y−9=0,7x+23y−53=0
d
None of these
detailed solution
Correct option is C
The slope of BD is 8/15 and the angle made by BD with DC and BC is 45∘. So, let the slope of DC be m . Then, tan45∘=±m−8151+815m or (15+8m)=±(15m−8) or m=237 and −723Hence, the equations of DC and BC are y−2=237(x−1) or 23x−7y−9=0 and y−2=−723(x−1) or 7x+23y−53=0Talk to our academic expert!
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