One diagonal of a square is along the line 8x - l5y=0 and one of its vertex is ( l, 2). Then the equations of the sides ofthe square passing through this vertex are

The slope of BD is 8/15 and the angle made by BD with DC and BC is 45∘. So, let the slope of DC be m . Then, tan⁡45∘=±m−8151+815m or  (15+8m)=±(15m−8) or  m=237 and −723Hence, the equations of DC and BC are  y−2=237(x−1) or  23x−7y−9=0 and y−2=−723(x−1) or  7x+23y−53=0