Equation of line in Straight lines

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Question

One diagonal of a square is3x-4y + 8 = 0 and one vertex is (-l , 1). Then the area of square is

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Solution

$Distance of vertex from diagonal = |\frac{- 3 - 4 + 8}{5}| = \frac{1}{5}$
$So, length of diagonal is \frac{2}{5} .$
$∴ Area of square = \frac{1}{2} \times \frac{2}{5} \times \frac{2}{5} = \frac{2}{25} sq. unit$

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