One diagonal of a square is 3x−4y+8=0 and one vertex is −1,1, then the area of square is

Let ABCD be square having vertex A−1,1One diagonal is 3x−4y+8=0; clearly, it is BD.Let O be centre of the square.∴  OA=OB=−3−4+85=15Area of square =4×ΔAOB=412×OA×OB=412×15×15=225sq.units