One of the diagonals of a square is the portion of the line x2+y3=2 intercepted between the axes. Then the extremities of the other diagonal are
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a
(5,5), (-1,1)
b
(0,0), (4,6)
c
(0,0), (-1,1)
d
(5,5), (4,6)
answer is A.
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Detailed Solution
The equation of the other diagonal is x-2313=y-3213=r For the extremities of the diagonal, r=±13. Hence x−2=±3, y−3=±2x = 5, -1 and y = 5,1Therefore, the extremities of the diagonal are (5,5) and (-1,1)