One of the diameter of the circle circumscribing the rectangle ABCD is 4y=x+7 . If A_(−3,4),B(5,4) . Then the equation of the side DC¯ is
x=0
y=0
y=5
x=-2
⇒ Centre =(1,2);AB line slope =0;D=2S−B=(−3,0) ; Req. DC¯Eq is ⇒y=0