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$One of the diameter of the circle circumscribing the rectangle ABCD is 4 y = x + 7 .$ $If \underline{A} (- 3, 4), B (5, 4) . Then the equation of the side \bar{D C} is$

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x=0

y=0

y=5

x=-2

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detailed solution

Correct option is B

⇒ Centre =(1,2);AB line slope =0;D=2S−B=(−3,0) ; Req. DC¯Eq is ⇒y=0

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One of the diameter of the circle circumscribing the rectangle ABCD is 4y=x+7 . If A_(−3,4),B(5,4) . Then the equation of the side DC¯ is

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$One of the diameter of the circle circumscribing the rectangle ABCD is 4 y = x + 7 .$ $If \underline{A} (- 3, 4), B (5, 4) . Then the equation of the side \bar{D C} is$