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One of the diameters of the circle
$x^{2} + y^{2} - 12 x + 4 y + 6 = 0$ is given by

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x+y=0

x+3y=0

x=y

3x+2y=0

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detailed solution

Correct option is C

The coordinates of the centre of the circle x2+y2−12x+4y+6=0 are (6,−2)Clearly, the line x+3y=0 passes through this point Hence, x + 3 y = 0 is a diameter of the given circle

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One of the diameters of the circle x2+y2−12x+4y+6=0 is given by

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

One of the diameters of the circle
$x^{2} + y^{2} - 12 x + 4 y + 6 = 0$ is given by