One hundred identical coins, each with probability p, of showing up heads are tossed once. If $$0$$

Question

One hundred identical coins, each with probability p, of showing up heads are tossed once. If $$0$$ < p < $$1$$ and the probability of heads showing on $$50$$ coins is equal to that of heads showing on $$51$$ coins, then value of pis

Infinity Learn · Accepted Answer

$$P(x=50)=P(x=51)$$⇒$$100C50(p)50(1$$−$$p)50=100C51(p)51(1$$−$$p)49$$       [ formula $$P($$ $$x=r$$ $$)$$ $$=c(n$$,$$r)$$  $$qn-r$$·pr   ]                           ⇒$$1$$−$$pp=5051$$                                       $$($$  since  $$C(n$$,r $$)C(n$$,$$r-1)=n-r+1r$$ $$)$$⇒$$p=51101$$

One hundred identical coins, each with probability $p$ , of showing up heads are tossed once. If 0 < $p$ < 1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then value of $p$ is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

One hundred identical coins, each with probability p, of showing up heads are tossed once. If 0 < p < 1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then value of pis

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

One hundred identical coins, each with probability $p$ , of showing up heads are tossed once. If 0 < $p$ < 1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then value of $p$ is