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One hundred tickets are numbered as 00, 01, 02, ......, 09, 10, 11, ......, 99 and one ticket is drawn at random from them. If A is the event of getting 9 as the sum of the numbers on the ticket and B is the event of getting 0 as the product of the numbers on the ticket then P(A∩B)=

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a

1100

b

2100

c

10100

d

19100

answer is B.

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Detailed Solution

A=Sum 9, B=Product 0 A∩B= Sum of the two numbers is 9 and product 0 ={09, 90} n(S)=100 n(A∩B)=2 P(A∩B)=2100

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