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One lies between the roots of the equation −x2+ax+a=0,a∈R if and only if a lies in the interval

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An Intiative by Sri Chaitanya

a

12,∞

b

−12,∞

c

−∞,12

d

−∞,12

answer is A.

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Detailed Solution

−x+ax+a=0⇒ x2−ax−a=0 Let f(x)=x2−ax−a f(1)<0⇒ 1−a−a<0⇒ 1<2a⇒ a>12

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