One lies between the roots of the equation −x2+ax+a=0,a∈R if and only if a lies in the interval
12,∞
−12,∞
−∞,12
−x+ax+a=0⇒ x2−ax−a=0 Let f(x)=x2−ax−a f(1)<0⇒ 1−a−a<0⇒ 1<2a⇒ a>12