One of the limit point of the coaxial system of circles containing x2+y2−6x−6y+4=0,x2+y2−2x−4y+3=0, is
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a
(-1,1)
b
(-1,2)
c
(-2,1)
d
(-2,2)
answer is A.
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Detailed Solution
The equation of the family of coaxial system of circles haveing x2+y2−6x−6y+4=0 and x2+y2−2x−4y+3=0 two members isx2+y2−6x−6y+4+λ(−4x−2y+1)=0⇒ x2+y2−2x(3+2λ)−2y(3+λ)+4+λ=0Coordinates of centre of circle (i) are(3+2λ,3+λ).1Radius =(3+2λ)2+(3+λ)2−(4+λ)For limiting points, we must haveRadius =0⇒5λ2+17λ+14=0⇒λ=−2,−7/5Hence, limiting points are (−1,1) and (1/5,8/5)