Q.

One of the limit point of the coaxial system of circles containing x2+y2−6x−6y+4=0,x2+y2−2x−4y+3=0, is

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a

(-1,1)

b

(-1,2)

c

(-2,1)

d

(-2,2)

answer is A.

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Detailed Solution

The equation of the family of coaxial system of circles haveing x2+y2−6x−6y+4=0 and x2+y2−2x−4y+3=0 two members isx2+y2−6x−6y+4+λ(−4x−2y+1)=0⇒ x2+y2−2x(3+2λ)−2y(3+λ)+4+λ=0Coordinates of centre of circle  (i) are⁡(3+2λ,3+λ).1Radius =(3+2λ)2+(3+λ)2−(4+λ)For limiting points, we must haveRadius =0⇒5λ2+17λ+14=0⇒λ=−2,−7/5Hence, limiting points are (−1,1) and (1/5,8/5)
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