One ticket is selected at random from $$50$$ tickets numbered $$00$$, $$01$$, $$02$$, …, $$49$$. Then the probability that the sum of the digits on the selected ticket is $$8$$, given that the product of these digits is zero, equals

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Infinity Learn · Accepted Answer

S $$=$$ $${00$$, $$01$$, $$02$$, … $$49}Let$$ A be the event that sum of the digits on the selected ticket is $$8$$ thenA $$=$$ $${08$$, $$17$$, $$26$$, $$35$$, $$44}Let$$ B be the event that the product of the digits is zeroB $$=$$ $${00$$, $$01$$, $$02$$, $$03$$, … $$09$$, $$10$$, $$20$$, $$30$$, $$40}A$$∩$$B={8}Required$$ probability $$=P(A/B)=P(A$$∩$$B)P(B)=1501450=114$$

One ticket is selected at random from 50 tickets numbered 00, 01, 02, …, 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

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