Q.
One vertex of an equilateral triangle is (2,3) and the equation of one side is x-y+5=0. Then the equations to other sides are
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a
y−3=−(2±3)(x−2)
b
y−3=(2±1)(x−2)
c
y−3=(3±1)(x−2)
d
y−3=(5±1)(x−2)
answer is A.
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Detailed Solution
Let slope of another side is m tan600=m−11+m; m=−2±3
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