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One vertex of an equilateral triangle of side $‘ a ’$ lies at the origin and the other lies on the line $x = \sqrt{3} y$ then the third vertex is

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detailed solution

Correct option is B

y=13xm=tanθ=13θ=300And third vertex lies as y-axis i.e., (0, a)

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One vertex of an equilateral triangle of side ‘a’ lies at the origin and the other lies on the line x=3y then the third vertex is

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One vertex of an equilateral triangle of side $‘ a ’$ lies at the origin and the other lies on the line $x = \sqrt{3} y$ then the third vertex is