One vertex of the triangle having maximum area inscribed in the curve |z−2i|=2 is 2+2i .then Which of the following is/are a possible vertex (ices) of this triangle?

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−1+i(2+3)

−1−i(2+3)

1+i(2−3)

−1−i(2−3)

answer is A.

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Detailed Solution

A triangle having maximum area is equilateral triangle.z-2i2+2i-2i=ei2π3z=-1+2+3i

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