Q.
An ordered pair (α, β)for which the system of linear equations (1+α) x+βy+z=2,αx+(1+β) y+z=3, αx+βy+2z=2 has a unique solution is
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a
(1, −3)
b
(−3, 1)
c
(2, 4)
d
(−4, 2)
answer is C.
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Detailed Solution
The condition for a non-homogeneous system to have a unique solution is Δ≠0⇒1+αβ1α1+β1αβ2≠0⇒R2→R2−R3R1→R1−R3, 10-101-1αβ2 ≠ 0⇒α+β+2≠0⇒(α, β)=(2, 4)is the only possible answer
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