An ordinary dice is rolled for a certain number of times. If the probability of getting an odd number $$2$$ times is equal to the probability of getting an even number $$3$$ times, then the probability of getting an odd number for odd number of times is:

Question

Infinity Learn · Accepted Answer

$$P(odd$$ no. $$twice)$$ $$=$$ $$P(even$$ no. $$thrice)$$⇒  $$nC212n=$$ $$nC312n$$⇒$$n=5success$$ is getting an odd number then $$P(odd$$ $$successes)$$ $$=$$ $$P(1)$$ $$+$$ $$P(3)$$ $$+$$ $$P(5)=$$  $$5C1125+$$ $$5C3125+5C5125=1625=12$$

An ordinary dice is rolled for a certain number of times. If the probability of getting an odd number 2 times is equal to the probability of getting an even number 3 times, then the probability of getting an odd number for odd number of times is:

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