First slide

Cartesian plane

Question

Orthocentre of the triangle whose sides are given by $4 x - 7 y + 10 = 0, x + y - 5 = 0$ and $7 x + 4 y - 15 = 0$ is

Moderate

A

(-1, - 2)
B

(1, -2)
C

(- l, 2)
D

(1, 2)

Solution

The lines $4 x - 7 y + 10 = 0$ and $7 x + 4 y - 15 = 0$
are perpendicular and their point of intersection is (1, 2).
Hence, the orthocentre is at (1, 2).

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