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Questions  

Orthocentre of the triangle whose sides are given by 4x7y+10=0,x+y5=0 and 7x+4y15=0 is

a
(-1, - 2)
b
(1, -2)
c
(- l, 2)
d
(1, 2)

detailed solution

Correct option is D

The lines 4x−7y+10=0 and 7x+4y−15=0 are perpendicular and their point of intersection is (1, 2).Hence, the orthocentre is at (1, 2).

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