Orthogonal trajectories of family of the curve x23+y23=a23 , whose ' a ' is an arbitrary constant is
x2/3-y2/3=c
x4/3-y4/3=c
x4/3+y4/3=c
x1/3-y1/3=c
23x-13+23y-13dydx=0→dydx=-y13x13 Replace dydx by −dxdy∴dxdy=y13x13⇒∫x13dx=∫y13dy⇒x43−y43=c