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Questions  

 Orthogonal trajectories of family of the curve x23+y23=a23 , whose ' a ' is an arbitrary constant is 

a
x2/3-y2/3=c
b
x4/3-y4/3=c
c
x4/3+y4/3=c
d
x1/3-y1/3=c

detailed solution

Correct option is B

23x-13+23y-13dydx=0→dydx=-y13x13 Replace dydx by −dxdy∴dxdy=y13x13⇒∫x13dx=∫y13dy⇒x43−y43=c

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