P(m,n)(m,n∈N) is any point in the interior of the quadrant formed bye the pair of lines xy=0 and two lines 2x+y-2=0 and 4x+5y=20 then the possible number of positions of the points P is
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a
4
b
5
c
6
d
11
answer is C.
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Detailed Solution
m,n∈N,2m+n−2>0 and 4m+5n-20<0 possible pairs are (1,1), (1,2), (1,3), (2,1), (2,2), (3,1)Total = 6