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P1 and P2 are points on either of the two lines y−3|x|=2 at a distance of 5 units from their point of intersection. The coordinates of the foot of perpendiculars drawn from P1,P2 on the bisector of the angle between the given lines is

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a

(0,2−532)

b

(0,1−532)

c

(0,2+532)

d

(0,1+532)

answer is C.

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Detailed Solution

y=3x+2 (x>0).......(1)y=−3x+2 (x<0).......(2)In ΔDEC, CDCE=cos300CD=5cos300=5.32⇒OD=OC+CD=2+532So, the coordinates of the foot of perpendicular are 0.2+532

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