P is a point on the hyperbola x2a2−y2b2=1S S and S′ are its foci. Statement-1: Product of the lengths of the perpendiculars from S and S′ on the tangent at P is equal to Statement-2: PS−PS′=2a.
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a
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1
b
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1
c
STATEMENT-1 is True, STATEMENT-2 is False
d
STATEMENT-1 is False, STATEMENT-2 is True
answer is B.
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Detailed Solution
Let P(asecθ,btanθ) equation of the tangent at P is xasecθ−ybtanθ=1Product of the lengths of the perpendiculars from (esecθ−1)(esecθ+1)sec2θa2+tan2θb2=a2b2e2sec2θ−1a2e2−1sec2θ+tan2θ=b2So statement-1 is trure.For statement-2, by definition of hyperbola distance of P from a focus is e times its distance from the corresponding directrix. So PS=ex−ae and PS′=ex+ae⇒PS−PS′=2aThus statement-2 is also true but does not justify statement-1.
P is a point on the hyperbola x2a2−y2b2=1S S and S′ are its foci. Statement-1: Product of the lengths of the perpendiculars from S and S′ on the tangent at P is equal to Statement-2: PS−PS′=2a.