Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

P is a point on the hyperbola x2a2−y2b2=1S S and S′ are its foci. Statement-1: Product of the lengths of the perpendiculars from S and S′ on the tangent at P is equal to Statement-2: PS−PS′=2a.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

b

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

c

STATEMENT-1 is True, STATEMENT-2 is False

d

STATEMENT-1 is False, STATEMENT-2 is True

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let  P(asec⁡θ,btan⁡θ) equation of the tangent at P is  xasec⁡θ−ybtan⁡θ=1Product of the lengths of the perpendiculars from (esec⁡θ−1)(esec⁡θ+1)sec2⁡θa2+tan2⁡θb2=a2b2e2sec2⁡θ−1a2e2−1sec2⁡θ+tan2⁡θ=b2So statement-1 is trure.For statement-2, by definition of hyperbola distance of P from a focus is e times its distance from the corresponding directrix. So PS=ex−ae and PS′=ex+ae⇒PS−PS′=2aThus statement-2 is also true but does not justify statement-1.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
P is a point on the hyperbola x2a2−y2b2=1S S and S′ are its foci. Statement-1: Product of the lengths of the perpendiculars from S and S′ on the tangent at P is equal to Statement-2: PS−PS′=2a.