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Questions  

P is a point on the parabola y2=4ax whose ordinate
is equal to its abscissa and PQ is a focal chord, R
and S are the feet of the perpendiculars from P and
Q respectively on the tangent at the vertex, T is the
foot of the perpendicular from Q to PR, area of the
triangle PTQ is

a
75a2/4
b
85a2/2
c
75a2/8
d
45a2/2

detailed solution

Correct option is C

P(4a,4a),Q(a/4,−a),R(0,4a),S(0,−a)T(a/4,4a). so area of the ∆PTQ is 12×PT∣×QT=124a−a4×5a=758a2 .

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