P is a point on the parabola y2=4ax whose ordinateis equal to its abscissa and PQ is a focal chord, Rand S are the feet of the perpendiculars from P andQ respectively on the tangent at the vertex, T is thefoot of the perpendicular from Q to PR, area of thetriangle PTQ is
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a
75a2/4
b
85a2/2
c
75a2/8
d
45a2/2
answer is C.
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Detailed Solution
P(4a,4a),Q(a/4,−a),R(0,4a),S(0,−a)T(a/4,4a). so area of the ∆PTQ is 12×PT∣×QT=124a−a4×5a=758a2 .