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Q.

P is a point in the plane of triangle ABC such that area ∆PAB = area ∆PBC = area ∆PCA then the number of possible positions  of P  is

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answer is 4.

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Detailed Solution

The centroid of the triangle and the fourth vertex of the three parallelograms formed by the given points will be required number of points  (taking the order of  vertices into consideration)
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