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$P$ is a point on $x -$ axis, $Q$ is a point on y-axis. Both are equidistant from the points $(7, 6)$ and $(3, 4)$ . Distance between $P$ and $Q$ is

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Correct option is C

Let the coordinates of P be (x, 0) and of Qbe (0,y), then(x−7)2+62=(x−3)2+42⇒x=15/2and 72+(y−6)2=32+(y−4)2⇒y=15So coordinates of P are (15/2, 0) and of Q are (0, 15)⇒ PQ=1522+(15)2=1552

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P is a point on x-axis, Q is a point on y-axis. Both are equidistant from the points (7, 6) and (3, 4). Distance between P and Q is

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$P$ is a point on $x -$ axis, $Q$ is a point on y-axis. Both are equidistant from the points $(7, 6)$ and $(3, 4)$ . Distance between $P$ and $Q$ is