Q.

P  and Q  are two variable points on the axes of x  and y  respectively such that |OP|+|OQ|=α , then the locus of foot of perpendicular from (0, 0)  on PQ  is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

(x+y)(x2+y2)=a(x−y)

b

(x−y)(x2−y2)=axy

c

(x+y)(x2+y2)=axy

d

(x+y)(x2−y2)=axy

answer is C.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Let PQ¯  be xα+yβ=1  equation of the circle passing through O,  P,  R  is x2+y2−αx=0.⇒α=x2+y2x where Ris foot of perpendicularSimilarly β=x2+y2y  ∴   |α|+|β|=aNow eliminate α, β
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
P  and Q  are two variable points on the axes of x  and y  respectively such that |OP|+|OQ|=α , then the locus of foot of perpendicular from (0, 0)  on PQ  is