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By Expert Faculty of Sri Chaitanya
a
a tautology
b
a contradiction
c
neither a tautology nor a contradiction
d
None of these
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Correct option is B
(p∧~q)∧(~p∧q) ≡(p∧~p)∧(~q∧q) ≡f∧f ≡f (By using associative laws and commutative laws)Therefore, (p∧~q)∧(~p∧q) is a contradiction.
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