P1:y2=49x and P2:x2=4ay are two parabolas. Equation of a tangent to the parabola P1 at a point where it intersects the parabola P2 is:
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a
2x−y−4a=0
b
y=0
c
x−2y+4a=0
d
x−y=0
answer is C.
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Detailed Solution
Two parabolas intersect at the points (0, 0) and (4a, 4a).Equation of the tangent to P1 at (0, 0) is x = 0 and at (4a, 4a) is y(4a)=2a(x+4a)⇒ x−2y+4a=0