Q.

P1:y2=49x  and P2:x2=4ay are two parabolas. Equation of a tangent to the parabola P1 at a point where it intersects the parabola P2 is:

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2x−y−4a=0

b

y=0

c

x−2y+4a=0

d

x−y=0

answer is C.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Two parabolas intersect at the points  (0, 0)  and (4a, 4a).Equation of the tangent to P1 at (0, 0) is x = 0 and at (4a, 4a) is y(4a)=2a(x+4a)⇒ x−2y+4a=0
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon