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A pair of numbers is picked up randomly (without replacement) from the set {1, 2, 3,5, 7, 11, 12, 13, 17, 19). The probability that the number 11 was picked given that the sum of the numbers was even is nearly

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a
0.1
b
0.125
c
0.24
d
0.18

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detailed solution

Correct option is C

Let Abe the event that 11 is picked and B be the event that sum is even. The number of ways of selecting 11 along with one more odd number is n(A∩B)=7C1. The number of ways of selecting either two even numbers or selecting two odd numbers is n(B)=1+8C2. ∴ P(A/B)=P(A∩B)P(B)=729=0.24


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