The pairs a→,b→ and c→,d→ each determine a plane. Then the planes are parallel if
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a
(a→×c→)×(b→×d→)=0→
b
(a→×c→)⋅(b→×d→)=0→
c
(a→×b→)×(c→×d→)=0→
d
(a→×b→)⋅(c→×d→)=0→
answer is C.
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Detailed Solution
a→×b→ is a vector perpendicular to the plane a→ and b→ Similarly c→×d→ is a vector perpendicular to the plane containing c→ and d→. Thus, the two planes will be parallel if their normals, i.e., a→×b→ and c→×d→ are parallel. Thus(a→×b→)×(c→×d→))=0→