Q.

For the parabola (1+k)y2=x at three points P,Q,R tangents are drawn and  they form triangle ABC . The circum circle of A,B,C is x2+y2-5x-4y+6=0 then k=

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a

−32

b

14

c

-78

d

-1112

answer is C.

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Detailed Solution

Circle passing through focus (a,0)⇒a2−5a+6=0⇒a=2,a=3⇒14k+1=2 or 3⇒k=−78,−1112
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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For the parabola (1+k)y2=x at three points P,Q,R tangents are drawn and  they form triangle ABC . The circum circle of A,B,C is x2+y2-5x-4y+6=0 then k=