A parabola touches the bisectors of the angle obtained by the lines x+2y+3=0 and 2x+y+3=0 at the points (1,1) and (0,-2) .
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a
Focus of parabola is 15,-75
b
length of latus rectum is 16253/2
c
Focus of parabola is 25,75
d
length of latus rectum is 1653/2
answer is A.
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Detailed Solution
The equations of the bisectors are given by x-y=0 and x+y+2=0 The bisectors intersect at the point (-1,-1) ,which lies on the directrix since the angular bisectors are perpendicular. let M=0,-2, N=1,1 Focus S is the foot of ⊥ from P to MN i.e. point of intersection of lines MN(3x-y-2=0) and PS(x+3y+4=0) PS is perpendicular to MN and passing through P solve the equations MN and PS , we get Focus S is 15,-75MS=25,NS=425 Length of latus rectum =222542525+425=16253/2 (∵ H.M. of segments of focal chord is semi latus-rectum)