For the parabola y2+8x−12y+20=0 which ofthe following in not correct

(y−6)2=−8(x−2) or Y2=4AX where Y=y−6X=x−2,A=−2, vertex is  (2,6),  focus is (X=A,Y=0)i.e., (0, 6) axis isY = 0 i.e. y = 6.and length of thelatus rectum =|4A|=8.