A particle acted on by constant forces f¯=4i^+3j^-3k^ and g→=3i^+j^-k^ experiences a displacement from the point a→=i^+2j^+3k^ to the point b→=5i^+4j^+k^ . The total work done by the forces is

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answer is 44.

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Detailed Solution

Resultant F→=7i^+4j^−4k^d→=(5i^+4j^+k^)−(i^+2j^+3k^)=4i^+2j^−2k^∴W=F→⋅d→ =(7i^+4j^−4k^)(4i^+2j^−2k^) =28+8+8=44

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