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Q.

A particle moves according to the law S=2t3−6t2+7t−6 . The velocity when the acceleration is zero is

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a

10  unit/sec

b

1  unit/sec

c

83  unit/sec

d

5  unit/sec

answer is B.

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Detailed Solution

s=2t3−6t2+7t−6 v=6t2−12t+7a=12t−12=0      when t = 1v=6−12+7=1unit/sec
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