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Q.

A particle moves along a line by then the distance traveled by S=23t3−6t2+16t the particle before it first comes to rest is

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a

20

b

403

c

173

d

15

answer is B.

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Detailed Solution

S=23t3−6t2+16t         v=2t2−12t+16=0         t2−6t+8=0         (t−2)(t−4)=0  ⇒t=2,4         S=403
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