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Q.

The particle moves along a straight line and its velocity at a distance 'l' from the origin is Ka2−l2  . Then the acceleration of the particle is

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a

K

b

−K2

c

Kl

d

−K2l

answer is D.

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Detailed Solution

v=ka2−ℓ2 dvdt=k1(−2ℓ)2a2−ℓ2×ν   dvdt=−kℓa2−ℓ2×ka2−ℓ2 = −k2ℓ
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