$$20$$ passengers are to travel by a double decked bus which can accommodate $$13$$ in the upper deck and $$7$$ in the lower deck. The number of ways that they can be distributed if $$5$$ refuse to sit in the upper deck and $$8$$ refuse to sit in the lower deck is

Question

Infinity Learn · Accepted Answer

Passengers refusing to sit in the lower deck (resp$$. upper $$deck) will sit in the upper deck $$(resp$$. lower $$deck)5$$ passengers will sit only in the lower deck and $$8$$ passengers will sit in the upper deck.  Remaining passengers $$=20-(5+8)=7Seats$$ remaining in lower $$deck=7$$−$$5=2$$ number of ways of filling $$2$$ seats in the lower deck $$=C2$$   $$7=21Corresponding$$ to each choice, the remaining  $$5=7$$–$$2$$ passengers will sit in the upper deck. number of choice $$=21$$

20 passengers are to travel by a double decked bus which can accommodate 13 in the upper deck and 7 in the lower deck. The number of ways that they can be distributed if 5 refuse to sit in the upper deck and 8 refuse to sit in the lower deck is

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