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$Period of f (x) = \cos (| \sin x | - | \cos x |) is$

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2π

π2

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Correct option is C

let fx =cos sinx-cosx ⇒fπ2+x=cos sinπ2+x-cosπ2+x = coscosx--sinx = cos sinx-cosx since cos-x=cosx =fx period of f(x) = π2 since π2 is the least positive value satisfying the above condition.

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Period of f(x)=cos⁡(|sin⁡x|−|cos⁡x|) is

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$Period of f (x) = \cos (| \sin x | - | \cos x |) is$