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a
2π
b
π
c
π2
d
None of these
answer is D.
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Detailed Solution
Let f (T + x) = f (x) ⇒ cos (T + x)2 = cos x2⇒ (T + x)2 = 2nπ ± x2Clearly, from here, no positive value of T independent of x is possible because x2 on R.H.S. can be cancelled only when T = 0.∴ f (x) is a non periodic function.