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The period of the function f(x)=3x+3[3x+3]+sinπx2, where [x] denotes the greatest integer ≤ x, is

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a
4
b
1
c
2
d
Non-periodic

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detailed solution

Correct option is A

3x + 3 – [3x + 3] has the period 1 and sin πx2 has the period 2ππ/2 i.e., 4. Therefore, the period of f (x) is L.C.M. (1, 4) = 4.


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